الفزعــــــــــــــــــــــــــــه ..

#include <stdio.h>
#include <math.h>

// Function Prototype

void get_corners(double x[], double y[]);
void output_corners(double x[], double y[]);
double polygon_area(double x[], double y[], double sum);
double polygon_price(double sum);

int main(void)
{

double x[20], y[20], sum, price, area; // Defining Varuables

// Function Call

get_corners(x, y);
output_corners(x, y);

sum = polygon_area(x, y, sum);
price = polygon_price(sum);

// Prints the area and the price
printf("\nArea = %.6f m2,%4cPrice = %.6f Dhs\n\n", sum, ' ', price);

return 0;
}

// User-Defined Functions

void get_corners(double x[], double y[])
{
int i, n_points, n_corners;

// Asks user for Number of Corners
printf("Enter Number of Corner Points: ");
scanf("%d", &n_corners);

// if Number of Corners the program exits
if(n_corners < 3)
{
printf("\n\nNumber of Corners are less than 3\n\n");
exit(0);
}

n_points = n_corners +1;

// Asks user for (x, y)
for(i = 0; i < n_points; i++)
{
printf("Enter (x, y) for point %d: ", i);
scanf("%lf%lf", &x[i], &y[i]);
}

// If first and last cordinates are not same the program exits
if(x[0] != x[n_points - 1] || y[0] != y[n_points - 1])
{
printf("\n\nError\n\n");
exit(0);
}
}

void output_corners(double x[], double y[])
{
int i, n_points;

// Prints the title of the table
printf("\n x(m) y(m)");
printf("\n-------------------------\n");

// Prints the table
for(i = 0; i <= n_points - 1; i++)
{
printf(" %.3f%6c%.3f\n", x[i], ' ', y[i]);
}
printf("-------------------------\n");
}

double polygon_area(double x[], double y[], double sum)
{
sum = 0.0;
int i, n_points;

// Calculates the Area of the Polygon
for(i = 0; i < (n_points - 1); i++)
{
sum = sum + ((x[i+1] + x[i]) * (y[i+1] - y[i]));
}

sum = fabs(sum)/2.0;

return(sum);
}

double polygon_price(double sum)
{
double price;

// Calculates the Price of the land of that area
if(sum < 500.00)
{
price = sum * 3000.00;
}

else if( 500.00 <= sum && sum < 2000.00)
{
price = sum * 3500.00;
}

else if( 2000.00 <= sum && sum < 4000.00)
{
price = sum * 4000.00;
}

else
{
price = sum * 5000.00;
}

return(price);
}

حماااااد عندي بروجيكت البروغرامنغ و تسليمه باجر

السؤال هو

/* Write a program that has a function multiple that determines a pair of integers whether the second integer is a multiple of the first.

The function should take two integer arguments and return 1(true) if the second is a multiple of the first, and 0(false) otherwise.

Use this function in a program that inputs a series of pairs of integers.*/

أنا حلي هو








بس هم طالبين أن سلسلة الاعداد إلي في الوايل تطلع حبة حبة

مش مجموع شرات حلي رغم أن من المفروض تطلع حبة حبة بس لما أشغل البرنامج إلي سويته

يطلع لي المجموع

سؤالي لك شو أحطي الكونديشن للوايل لوووب

الحمد لله خلصته و سلمته لسير




شوف الكومينت إستعملت طريقتك

بما أن الصورة عملاقة

فبعطيكم الكود


#include
int multiple ( int num1 , int num2 ); // function prototype
int
main(void)
{
int num1,num2,time,mult,X,Y,N;
printf("\nThis program has a function multiple that determines a pair of integers\n");
printf("\nwhether the second integer is a multiple of the first.\n\n\n\n");
printf("\n\nTimes to repetetion ?\n\n");
scanf("%d",&time);
// loop for repeats the questions
for ( N = 1 ; N <= time ; N++)
{
printf("\nEnter two integer number except (0)\n");
printf("Then press . I will tell you if \n");
printf("The second integer is a multiple of the first.\n");
printf("\nInteger #1 = \n");
scanf("%d",&num1);
printf("Integer #2 = \n\n"); // num2 is greater than num1
scanf("%d",&num2);
mult = multiple(num1,num2);
// Condition that determines weather the second number is a multiple of the first or not
if ( mult )
{
printf("\n\n The Integer #2 is a multiple of the Integer #1 \n\n");
}
else {
printf("\n\n The Integer #2 is not a multiple of the Integer #1 \n\n");
}
} // End the loop
return(0);
}
// the multiple function
int
multiple ( int X , int Y)
{
return ! (Y%X);
}